Nejednakost 1

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5 years 5 dani ago #145 by Buldi
Nejednakost 1 was created by Buldi
neka sua,b,c
nenegativni realni brojevi iab+bc+ca=3
.Dokazati nejednakost
3+8sum_{cyc}frac{b^2c^2(3b^2+3c^2+7a^2)}{7a^2+6bc}ge9(a^2+b^2+c^2)

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